3.6=12t-2t^2

Solution for 3.6=12t-2t^2 equation:

3.6=12t-2t^2

We move all terms to the left:

3.6-(12t-2t^2)=0

We get rid of parentheses

2t^2-12t+3.6=0

a = 2; b = -12; c = +3.6;
Δ = b2-4ac
Δ = -122-4·2·3.6
Δ = 115.2
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12)-\sqrt{115.2}}{2*2}=\frac{12-\sqrt{115.2}}{4}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12)+\sqrt{115.2}}{2*2}=\frac{12+\sqrt{115.2}}{4}
$